Question

In methyl alcohol solution, bromine reacts with ethylene to yield $BrCH_{2}CH_{2}OCH_{3}$ in addition to 1, 2-dibromoethane because.

• A. The ion formed initially may react with $Br^{-}$ or $CH_{3}OH$
• B. The methyl alcohol solvates the bromine
• C. The reaction follows Markownikoff's rule
• D. This is a free-radical mechanism

Answer 1

Answer: (A)

The ion formed initially may react with $Br^{-}$ or $CH_{3}OH$

Answer 2

$CH_{2} = CH_{2} + Br_{2}\overset{\quad CH_{3}OH\quad}{\rightarrow}$

$\underset{Br}{\underset{|}{C} ⥂ H_{2} -}\underset{Br}{\underset{|}{C} ⥂ H_{2} +}Br - CH_{2} - CH_{2} - O - CH_{3}$