Question

In meldey experiment, 16 kg mass is hanged with wire and tuning fork is vibrated with its prong parallel to wire. Wire vibrates with 2 loops. When an unknown mass is hanged with wire and tuning fork is vibrated with its prong perpendicular to wire, wire vibrates in 8 loops. Unknown mass is –

• A. 1 kg
• B. 2 kg
• C. 6 kg
• D. 4 kg

Answer 1

Answer: (D)

4 kg

Answer 2

n = $\frac{n\sqrt{F/\mu}}{2\mathcal{l}}$

As l & m are not changing

n µ $n\sqrt{F}$

$\frac{\nu_{2}}{\nu_{1}}$ = $\frac{n_{2}\sqrt{F_{2}}}{n_{1}\sqrt{F_{1}}}$

Ž $\frac{\nu_{2}}{\nu_{1}}$ = $\frac{n_{2}}{n_{1}}$ $\sqrt{\frac{m_{2}}{m_{1}}}$

\ m₂ = $\left( \frac{\nu_{2}}{\nu_{1}} \times \frac{n_{1}}{n_{2}} \right)^{2}$. m₁

Ž m₂ = 4 kg