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Question: In \(\operatorname { cosec } A ( \sin B \cos C + \cos B \sin C ) =\)...

In cosec⁡A(sin⁡Bcos⁡C+cos⁡Bsin⁡C)=\operatorname { cosec } A ( \sin B \cos C + \cos B \sin C ) =

A

c/ac / a

B

a/ca / c

C

1

D

c/abc / a b

Answer

1

Explanation

Solution

(bacos⁡C+cacos⁡B)=\left( \frac { b } { a } \cos C + \frac { c } { a } \cos B \right) =1; (by projection rule)