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Question: In making an alloy a substance of specific gravity \( {s_1} \) and mass \( {m_1} \) is mixed with an...

In making an alloy a substance of specific gravity s1{s_1} and mass m1{m_1} is mixed with another substance of specific gravity s2{s_2} and mass m2{m_2} ; then the specific gravity of the alloy is:
A. (m1+m2s1+s2)\left( {\dfrac{{{m_1} + {m_2}}}{{{s_1} + {s_2}}}} \right)
B. (s1s2m1+m2)\left( {\dfrac{{{s_1}{s_2}}}{{{m_1} + {m_2}}}} \right)
C. m1+m2(m1s1+m2s2)\dfrac{{{m_1} + {m_2}}}{{\left( {\dfrac{{{m_1}}}{{{s_1}}} + \dfrac{{{m_2}}}{{{s_2}}}} \right)}}
D. (m1s1+m2s2)m1+m2\dfrac{{\left( {\dfrac{{{m_1}}}{{{s_1}}} + \dfrac{{{m_2}}}{{{s_2}}}} \right)}}{{{m_1} + {m_2}}}

Explanation

Solution

Before proceeding to the question, let us first have a basic idea of the term related to the query that is specific gravity. The specific gravity of an object is the ratio of its density to that of a reference substance. The specific gravity can inform us whether an object will sink or float in our reference substance depending on its value. Water is commonly used as a reference substance since it has a density of 1gram per millilitre or 1 gram per cubic centimetre.

Complete step by step answer:
Now, coming to the question;
Specific gravity of alloy is given by;
=DensityofalloyDensityofwater= \dfrac{{Density\,of\,alloy}}{{Density\,of\,water}}
=MassofalloyVolumeofalloy×Densityofwater= \dfrac{{Mass\,of\,alloy}}{{Volume\,of\,alloy \times Density\,of\,water}}
=m1+m2(m1ρ1+m2ρ2)×ρw= \dfrac{{{m_1} + {m_2}}}{{\left( {\dfrac{{{m_1}}}{{{\rho _1}}} + \dfrac{{{m_2}}}{{{\rho _2}}}} \right) \times {\rho _w}}}
Proceeding further in the equation;
=m1+m2m1ρ1rhow+m2ρ2rhow= \dfrac{{{m_1} + {m_2}}}{{\dfrac{{{m_1}}}{{\dfrac{{{\rho _1}}}{{rh{o_w}}}}} + \dfrac{{{m_2}}}{{\dfrac{{{\rho _2}}}{{rh{o_w}}}}}}}
=m1+m2(m1s1+m2s2)= \dfrac{{{m_1} + {m_2}}}{{\left( {\dfrac{{{m_1}}}{{{s_1}}} + \dfrac{{{m_2}}}{{{s_2}}}} \right)}}
Therefore the specific gravity of the alloy is m1+m2(m1s1+m2s2)\dfrac{{{m_1} + {m_2}}}{{\left( {\dfrac{{{m_1}}}{{{s_1}}} + \dfrac{{{m_2}}}{{{s_2}}}} \right)}}
So, the correct option is: C. m1+m2(m1s1+m2s2)\dfrac{{{m_1} + {m_2}}}{{\left( {\dfrac{{{m_1}}}{{{s_1}}} + \dfrac{{{m_2}}}{{{s_2}}}} \right)}} .

Note:
Specific gravity is widely used in chemical science and technology due to its ease of measurement; for example, determining the specific gravity is part of the standard characterisation of a new liquid compound. Most organic molecules having solely carbon, hydrogen, and oxygen have a specific gravity of less than one. The Westphal balance, pycnometer, and hydrometer are examples of equipment used to measure specific gravity.