Question
Question: In \[M{n_2}{(CO)_{10}}\] no. of metal-metal bonds and no. of \[CO\] bridges are \['x'\] and \[F{e_2}...
In Mn2(CO)10 no. of metal-metal bonds and no. of CO bridges are ′x′ and Fe2(CO)9 no. of metal -metal bonds and no. of CO bridges are y. Then x+y
Solution
Metal–metal bonds form due to the attractive interactions between metal centers. Bridging bonds are formed when a ligand connects two or more central atoms together. The simplest method to solve this question is to draw the structure of both the compounds and count the metal–metal bonds and bridge bonds.
Complete step-by-step answer: Let’s draw the structure of Mn2(CO)10 and Fe2(CO)9.
Complete step by step solution:
As you can see, in Mn2(CO)10, there is only one metal–metal bond between manganese atoms. There is no bridge bond in Mn2(CO)10 as no ligand is connecting the two manganese atoms. While, in Fe2(CO)9, there is one metal–metal bond between ferrous atoms and three bridge bonds between CO and Fe.
To calculate the value of x+y, there are two cases:
x represents the no of metal – metal bonds and y represents the no of CO bridge bonds:
Total number of metal – metal bonds in Mn2(CO)10=1
Total number of metal – metal bonds in Fe2(CO)9=1
x=1+1=2
Total number of CO bridge bonds in Mn2(CO)10=0
Total number of CO bridge bonds in Fe2(CO)9=3
y=0+3=3
Hence,
x+y=2+3
x+y=5
x represents the total no of metal -metal bonds and bridge bonds in Mn2(CO)10 and y represents the total no of metal -metal bonds and bridge bonds in Fe2(CO)9:
Total number of bonds in Mn2(CO)10, x=1+0=1
Total number of bonds in Fe2(CO)9, y=1+3=4
Hence,
x+y=1+4
x+y=5
Hence, in both the cases, the value of x+y is 5.
Note:
Be careful while drawing the structure of compounds. Any error in the structure will lead to an incorrect answer. While counting the CO bridge bonds, do not count any metal - CO only bonds, count metal - CO- metal bonds. Remember that the ligands that connect two metal atoms form the bridge bonds.