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Question: In lab you measure out \[87.25{\text{ }}g\]of \[{C_4}{H_8}{O_4}\] for an experiment. How many mol is...

In lab you measure out 87.25 g87.25{\text{ }}gof C4H8O4{C_4}{H_8}{O_4} for an experiment. How many mol is this?

Explanation

Solution

As we know that, 11mole of any atom or molecule or ion contains Avogadro’s number (NA{N_A} ) of molecule
So, 1mole=6.022×1023atoms1\,mole\, = \,6.022\, \times \,{10^{23}}\,atoms
Therefore, for 11 molecule will be;
1atoms=16.022×1023moles1\,\,atoms\, = \,\dfrac{1}{{6.022\, \times \,{{10}^{23}}}}\,moles
So, the answer will be;
1atoms=1.66×1024moles1\,atoms\, = 1.66\, \times \,{10^{ - 24}}\,moles

Complete step-by-step answer: First, we need to calculate the number of moles of C4H8O4{C_4}{H_8}{O_4};
As we know that, the number of moles will be equal to the given mass divided by the molecular mass a compound.
Hence, the formula will be as follows,
n=massmolarmassn\,\, = \,\,\dfrac{{mass}}{{molar\,mass}}
Where,
n=n\, = the amount in moles (mol)(mol)
Mass will be in the terms of  (g)\;(g)
Molar mass will be in the terms of   (g/mol)\;(g/mol)
So, we need to calculate the moles of C4H8O4{C_4}{H_8}{O_4} .
first, we need to calculate the molar mass of C4H8O4{C_4}{H_8}{O_4}and then we need to calculate the moles.
Let’s calculate the molar mass of this compound C4H8O4{C_4}{H_8}{O_4};
The molar mass of carbon =12g/mol = \,12\,g/mol
We have four carbons so the overall molar mass for carbon will be;
=12×4=48g/mol= \,12\, \times \,4\, = \,48\,g/mol
The molar mass of hydrogen =1.0g/mol = \,1.0\,g/mol
We have eight hydrogens so the overall molar mass for hydrogen will be;
=1×8=8g/mol= \,1\, \times \,8\, = \,8\,g/mol
The molar mass of oxygen =16g/mol = \,16\,g/mol
We have four oxygen so the overall molar mass for oxygen will be;
=16×4=64g/mol= \,16\, \times \,4\, = \,64\,g/mol
Now the total molar mass of C4H8O4{C_4}{H_8}{O_4} will be;
=48+8+64= \,48\, + \,8\, + 64
=120g/mol= \,120\,g/mol
Now, the given mass of{C_4}{H_8}{O_4}$$$$ = \,87.25{\text{ }}g
Let’s substitute in the values;
n=87.25g120g/moln\,\, = \,\,\dfrac{{\,87.25\,g}}{{120\,g/mol}}\,
=0.727moles= \,0.727\,moles
So, for the 87.25 g87.25{\text{ }}g of C4H8O4{C_4}{H_8}{O_4}is 0.727moles0.727\,moles

Note: A mole is a unit measurement for the amount of substance in the international system of units i.e., SI unit. A mole of a particle or a mole of a substance is defined as 6.02214076×10236.02214076 \times {10^{23}} of a chemical unit, that can be ions, atoms, molecules, etc. Originally it was defined as, the number of atoms in 12 g12{\text{ }}g of carbon-12.