Question
Question: In \(K_{4}\left\lbrack Fe(CN)_{6} \right\rbrack,\) the E.A.N. of \(Fe\) is....
In K4[Fe(CN)6], the E.A.N. of Fe is.
A
33
B
35
C
36
D
26
Answer
36
Explanation
Solution
EAN =Atomic number – Oxidation state + 2 × number of Ligands = 26 – 2 + 2 (6) = 36.