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Question: In Joule’s Calorimeter experiment, when a current of \(1\) Ampere is passed through a coil for a kno...

In Joule’s Calorimeter experiment, when a current of 11 Ampere is passed through a coil for a known interval of time ‘t’, the temperature of water increases from 30C30^\circ Cto 33C33^\circ C. When a current 2A2A is passed through the same coil placed in the same quantity of water and for the same time, the temperature of water increases from 30C30^\circ C to,
A. 33CA.{\text{ }}33^\circ C
B. 36CB.{\text{ }}36^\circ C
C. 39CC.{\text{ }}39^\circ C
D. 42CD.{\text{ }}42^\circ C

Explanation

Solution

A Calorimeter is a device used to measure the amount of heat involved in a chemical or physical process. For example, when an exothermic reaction occurs in a calorimeter, the heat produced by the reaction is absorbed by the solution, which increases its temperature. The principle of Calorimeter indicates the law of conservation of energy.

Formulae Used: We will be using the relation of11) Heat is related to the rise in temperatureH=mcdTH = mcdT and 22) Joule’s equation of electrical heating H=i2RtH = {i^2}Rt

Complete step by step answer:
When a resistor absorbs electrical energy, it dissipates the energy in the form of heat H. If the resistor is placed in the calorimeter, the amount of heat produced can be measured when it is absorbed in the calorimeter. The heat Q produces a temperature rise dTdT. The resistor coil is immersed in the water in a calorimeter. The heat Q produces a temperature rise dTdT. The heat is related to dTdT
The heat generated in water that resulted in the temperature of water increases from 30C30^\circ Cto 33C33^\circ C is given by,
H=mcdTH = mcdT
Where m is the mass of water
dT=dT = (3330)=3(33 - 30) = 3 is the temperature difference.
Current passed through the coil, i1=1A{i_1} = 1A
Therefore H is equal to i2Rt{i^2}Rt
Where, i, R, and t are the current, resistance of the coil, and temperature respectively.
i2Rt=mcdT\Rightarrow {i^2}Rt = mcdT
Here R, t, C, and m remain the same, but current increased toi2=2A{i_2} = 2A
Hence, i22=mcdTi_2^2 = mcd{T'}
Dividing the two equations,
dTdT=2212\dfrac{{dT'}}{{dT}} = \dfrac{{{2^2}}}{{{1^2}}} (C)(^\circ C)
dT=12dT' = 12
Therefore, the final temperature=30+12=42C = 30 + 12 = 42^\circ C

Option D)D) 420C{42^0}C

Note: A Calorimeter is a device used to measure the amount of heat involved in a chemical or physical process. For example, when an exothermic reaction occurs in a calorimeter, the heat produced by the reaction is absorbed by the solution, which increases its temperature. The principle of Calorimeter indicates the law of conservation of energy.