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Question

Question: In \(\triangle A B C , \frac { \sin B } { \sin ( A + B ) } =\)...

In △ABC,sin⁡Bsin⁡(A+B)=\triangle A B C , \frac { \sin B } { \sin ( A + B ) } =

A

ba+b\frac { b } { a + b }

B

bc\frac { b } { c }

C

cb\frac { c } { b }

D

None of these

Answer

bc\frac { b } { c }

Explanation

Solution

sin⁡Bsin⁡(A+B)=sin⁡Bsin⁡C=bc\frac { \sin B } { \sin ( A + B ) } = \frac { \sin B } { \sin C } = \frac { b } { c }.