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Question: In identical cells each of e.m.f. E and internal resistance r are connected in series. An external r...

In identical cells each of e.m.f. E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is

A

nER+nr\frac { n E } { R + n r }

B

nEnR+r\frac { n E } { n R + r }

C

ER+nr\frac { E } { R + n r }

D

nER+r\frac { n E } { R + r }

Answer

nER+nr\frac { n E } { R + n r }

Explanation

Solution

Total e.m.f. = nE, Total resistance R + nr

⇒ i=nER+nri = \frac { n E } { R + n r }