Question

In $ICl_4^ -$ , the shape is square planar, the number of bond pair-lone pair repulsion at ${90^ \circ }$ are:
$A.$ $6$
$B.$ $8$
$C.$ $12$
$D.$ $4$

Answer 1

We can predict the number of bond pair-lone pair repulsions at${90^ \circ }$ by drawing its structure. The shape of $ICl_4^ -$ is square planar because it has four bond pairs and lone pairs. The geometry is octahedral.

Complete step-by-step answer: Before solving the question we have to look at the structure to determine their number of bond pair-lone pairs.
Now, the structure of $ICl_4^ -$ is,

Iodine $\left( I \right)$ has $7$ electron it its valence shell in $ICl_4^ -$eight electron participate in formation of compound
Shape of $ICl_4^ -$is square planar. Since its geometry is octahedral, lone pairs reside above and below the square planar. In $ICl_4^ -$each lone pair interacts with the $4$ bond pair.
So, Number of bond pair-lone pair repulsion=Total number of lone pairs multiplied by number of bond pairs by which they interact. We have two lone pairs and four bond pairs
Number of bond pairs-lone pairs repulsion$= 2 \times 4$
$= 8$
Thus, there is $8$ bond pairs-lone pairs repulsion at ${90^ \circ }$ . So, the correct option is $B.$

Note: Valence Shell Electron Pair Repulsion Theory $\left( {VSEPR} \right)$ .This is a very useful theory to predict the geometry or shape of a number of polyatomic molecules or ions on a non-transition element. This theory says that shapes of a species depend on the number of and nature of electron pairs surrounding the central atom of a species.
Table summarizes the relationship between the number of electron pairs that are bond pairs and lone pairs and the shape or geometry.

Total number of electron pairs	Shape
2	Linear
3	Trigonal planar
4	Tetrahedral
5	Trigonal bipyramidal
6	Octahedral
7	Pentagonal bipyramidal