Question

In hydrogen atom, when electron jumps from second to first orbit, then energy emitted is.

• A. – 13.6 eV
• B. – 27.2 eV
• C. – 6.8 eV
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

$E_{n_{1} \rightarrow n_{2}} = - 13.6\left\lbrack \frac{1}{n_{2}^{2}} - \frac{1}{n_{1}^{2}} \right\rbrack;n_{1} = 2\& n_{2} = 1$

$\Rightarrow E_{II} \rightarrow E_{I} = - 13.6 \times \frac{3}{4} = - 10.2\mspace{6mu} eV$