Solveeit Logo
Login

Question

Question: In hydrogen atom, an electron is revolving in the orbit of radius \(6.6 \times 10 ^ { 15 }\)rotation...

In hydrogen atom, an electron is revolving in the orbit of radius 6.6×10156.6 \times 10 ^ { 15 }rotations/second. Magnetic field produced at the centre of the orbit is

A

0.125wb/m20.125 \mathrm { wb } / \mathrm { m } ^ { 2 }

B

C

12.5wb/m212.5 \mathrm { wb } / \mathrm { m } ^ { 2 }

D

125wb/m2125 \mathrm { wb } / \mathrm { m } ^ { 2 }

Answer

12.5wb/m212.5 \mathrm { wb } / \mathrm { m } ^ { 2 }

Explanation

Solution

B=μ04π⋅2π(qv)rB = \frac { \mu _ { 0 } } { 4 \pi } \cdot \frac { 2 \pi ( q v ) } { r }

=10−7×2×3.14×(1.6×10−19×6.6×1015)0.53×10−10= 10 ^ { - 7 } \times \frac { 2 \times 3.14 \times \left( 1.6 \times 10 ^ { - 19 } \times 6.6 \times 10 ^ { 15 } \right) } { 0.53 \times 10 ^ { - 10 } } =12.5 Wb/m2= 12.5 \mathrm {~Wb} / \mathrm { m } ^ { 2 }