Solveeit Logo
Login

Question

Question: In hydrogen and hydrogen like atoms the ratio of difference of energies E<sub>4n</sub> – E<sub>2n</s...

In hydrogen and hydrogen like atoms the ratio of difference of energies E4n – E2n and E2n – En varies with atomic number Z and principle quantum number n as:

A

Z2n2\frac{Z^{2}}{n^{2}}

B

Z4n4\frac{Z^{4}}{n^{4}}

C

Zn\frac{Z}{n}

D

None of these

Answer

None of these

Explanation

Solution

E4n−E2nE2n−En\frac{E_{4n} - E_{2n}}{E_{2n} - E_{n}}=E116n2−E14n2E14n2−E1n2\frac{\frac{E_{1}}{16n^{2}} - \frac{E_{1}}{4n^{2}}}{\frac{E_{1}}{4n^{2}} - \frac{E_{1}}{n^{2}}}=14\frac{1}{4}= constant.