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Physics Question on Magnetic Field Due To A Current Element, Biot-Savart Law

In hydrogen a atom, an electron is revolving in the orbit of radius 0.53 �0.53\,� with 6.6×10156.6 \times 10^{15} radiations/s. Magnetic field produced at the centre of the orbit is

A

0.125 Wb/m20.125 \, Wb/m^2

B

1.25 Wb/m21.25 \, Wb/m^2

C

12.5 Wb/m212.5 \, Wb/m^2

D

125 Wb/m2125 \, Wb/m^2

Answer

12.5 Wb/m212.5 \, Wb/m^2

Explanation

Solution

The magnetic field
B=μ04π.2π(qv)rB= \frac{\mu_{0}}{4\pi} . \frac{2\pi\left(qv\right)}{r}
=10−7×2×3.14×(1.6×10−19×1.6×1015)0.53×10−10= 10^{-7} \times \frac{2\times 3.14\times \left(1.6\times 10^{-19}\times 1.6\times 10^{15}\right)}{0.53\times 10^{-10}}
=12.5 Wb/m3= 12.5\, Wb/m^{3}