Question
Question: In Huckel’s \((4n + 2)\pi \) rule for aromaticity, \(n\) represents ? A.Number of carbon atoms B...
In Huckel’s (4n+2)π rule for aromaticity, n represents ?
A.Number of carbon atoms
B.Number of rings
C.Whole number
D.Fractional number or integer or zero
Solution
Huckel gave the number of electrons / pi-bonds in an aromatic compound by this formula (4n+2)π . Here, ′n′ can be any positive natural number starting from zero .
Complete answer:
A compound is said to be aromatic if follows the following conditions –
-It is cyclic.
-If it is planar i.e. if all the atoms or bonds lie in the same plane.
-It has delocalised pi- electrons ( un-hybridised p-orbital) .
-Follows Huckel’s rule: which says that if a compound has (4n+2)π electrons and satisfies above three conditions ,it is an aromatic compound .
Here , n=0,1,2,3,4......
-This implies that n can be any number starting from zero .
When n=0, number of electrons =2
When n=1 , number of electrons =6 and so on .
-So the number of pi-electrons is 2,6,10,14,18...... and it follows the above three conditions, it falls into the category of aromatic compounds.
-If any compound doesn’t follow the given conditions ,it is either non-aromatic or anti-aromatic . If a compound is anti- aromatic , it has 4nπ electrons where the n is the whole number.
We can conclude that n is simply the whole number .
Hence, the correct option is C.
Note:
We have to keep in mind that n can never be any fractional value or negative value. It always has to be positive,where n is the number of electrons.