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Question: In how many ways can a mixed double tennis game be arranged from 7 married couples. If no husband an...

In how many ways can a mixed double tennis game be arranged from 7 married couples. If no husband and wife play in the same game ?
A. 28
B. 70
C. 210
D. 420

Explanation

Solution

In this particular question when we select two men from 7 couples then we can’t select two wives from the 7 womens because they can be the wife of selected men. So, we had to select wives from the 5 women (excluding wives of 2 men). And this could be done in reverse order also. Like first we selected two womens from 7. And after that select two men from the 5 men. And these men and women should be selected using the formula nCr=n!r!(nr)!{}^n{C_r} = \dfrac{{n!}}{{r!\left( {n - r} \right)!}} .

Complete step-by-step answer :
Now let us assume the 1st two husbands as X and Y and excluding their wives we had to assume two other ladies let say A and B out of 5 remaining ladies.
So, we can represent the 2 husbands with the formula as 7C2{}^7{C_2} and the 2 assumed ladies ( A and B ) can be represented as 5C2{}^5{C_2} because we cannot count the wives of X and Y(here).
Now these 7C2{}^7{C_2} husbands can team up with other ladies in
7C2=7!2!(72)!=21ways{}^7{C_2} = \dfrac{{7!}}{{2!\left( {7 - 2} \right)!}} = 21ways
And these 5C2{}^5{C_2} ladies can team up with other gents apart from their husband in
5C2=5!2!(52)!=10ways{}^5{C_2} = \dfrac{{5!}}{{2!\left( {5 - 2} \right)!}} = 10ways
So the total number of ways of selecting the players for mixed match = 7C2{}^7{C_2} * 5C2{}^5{C_2}
21×10=210ways\Rightarrow 21 \times 10 = 210ways
Now since we have calculated these number for men first and women second , we could also do this in reverse order .Therefore we have to multiply the obtained value with 2.
So, now required number of ways is 2 * 210 = 420.
Hence D is the correct option.

Note : In such type of questions in which we have to pair up or we have to team up the players by the formula of permutation and combinations nCr=n!r!(nr)!{}^n{C_r} = \dfrac{{n!}}{{r!\left( {n - r} \right)!}} are very helpful and make the solution easy and quickly as compared to the solution in other ways. And as here it is mentioned that it is a doubles tennis which means there must be 2 members in a team but the team members cannot be a couple by keeping these main points of question in mind we can solve the question.