Question

In how many ways can a committee of $5$ made out $6$ men and $4$ women containing atleast one woman?

• A. 246
• B. 222
• C. 186
• D. None of these

Answer 1

Answer: (A)

246

Answer 2

A committee of $5$ out of $6 + 4= 10$ can be
made in $^{10}C_5 = 252$ ways.
If no woman is to be included,
then number of ways $= \,^5C_5$ = 6
$\therefore$ the required number $= 252 -6 = 246$