Question

In how many ways can 5 boys and 5 girls sit in a circle so that no boys sit together

• A. 5! × 5!
• B. 4! × 5 !
• C. $\frac{5! \times 5!}{2}$
• D. None of these

Answer 1

Answer: (B)

4! × 5 !

Answer 2

Since total number of ways in which boys can occupy any place is $(5 - 1)! = 4!$ and the 5 girls can be sit accordingly in 5! ways. Hence required number of ways are 4 ! × 5 !.