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Question: In how many ways a team of 10 players out of 22 players can be made if 6 particular players are alwa...

In how many ways a team of 10 players out of 22 players can be made if 6 particular players are always to be included and 4 particular players are always excluded

A

22C1022C_{10}

B

18C318C_{3}

C

12C412C_{4}

D

{1+rx+r(r+1)2!x2+.....r(r+1)(r+2).....(r+n−1)n!xn+.....}\left\{ 1 + rx + \frac{r(r + 1)}{2!}x^{2} + .....\frac{r(r + 1)(r + 2).....(r + n - 1)}{n!}x^{n} + ..... \right\}

Answer

12C412C_{4}

Explanation

Solution

6 particular players are always to be included and 4 are always excluded, so total number of selection, now 4 players out of 12.

Hence number of ways = 12C412C_{4}.