Question

In heterolytic bond fission the formed carbanions are.
A) $s{p^3}$ hybridized.
B) Reactive towards the positive charge.
C) Has octet configuration.
D) All of these.

Answer 1

We know that a carbanion is often outlined as a charged particle during which an atom exhibits trivalence (implying it forms a complete of 3 bonds) and holds a proper charge whose magnitude is a minimum of -1. Once pi delocalization doesn't occur within the organic molecule (as it will in the case of aromatic compounds), carbanions usually assume a bent, linear, or a rhombohedral pyramidic molecular geometry. It’s vital to notice that everyone's carbanion is conjugate bases of some carbon acids.

Complete step by step answer:
-We must remember that in all carbanions, the lepton density is much targeted at the positively charged atom. Therefore, this carbon becomes a perfect purpose of attack for several electrophiles and alternative electron-deficient species. Furthermore, this carbanion has octet configuration.
Therefore, the option Band C is correct.
-As we know that every bond combined shares 2 electrons between the bonding atoms and lone pair consists of two unshared electrons. Therefore all it has via shared electrons and a couple of unshared electrons round the carbanion. Therefore it's $s{p^3}$ hybridized and pyramidic geometry.
Therefore, the option A is also correct.
Carbanion has all the mentioned properties. Therefore, the correct option is D.

Note:
We have to remember the following points about the stability of carbocation.
-The nucleophilicity and therefore the basicity of the carbanion are usually determined by the substituent teams that are hooked up to the charged carbon.
-The inductive effect, via that extremely negative substituent groups attached to the carbanion facilitate subdue the negative charge on that and create the molecule a lot stable. On the other hand, extremely positive substituent teams will increase the electric charge on the carbanion and, therefore, decrease the stability of the molecule.
-The resonance result, via that the delocalization of the electrons distributes the negative charge everywhere the carbanion, adding stability within the process.
-Aromatic systems add an excellent deal of stability to carbanions once they are given as a substituent cluster as a result of the resonance effect.
-Carbanions are detected within the answer part via nucleon nuclear magnetic resonance that is by the magnetic resonance spectroscopy.