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Question: In H2- O2 fuel cell the reaction occuring at cathode is...

In H2- O2 fuel cell the reaction occuring at cathode is

A

2 H2O + O2 + 4 e−→ 4 OH−\text{2 }\text{H}_{2}\text{O + }\text{O}_{2}\text{ + 4 }\text{e}^{-}\overset{\quad\quad}{\rightarrow}\text{ 4 O}\text{H}^{-}

B

2 H2 + O2→ 2 H2 O (l)\text{2 }\text{H}_{2}\text{ + }\text{O}_{2}\overset{\quad\quad}{\rightarrow}\text{ 2 }\text{H}_{2}\text{ O }(l)

C

H++ OH −→H2OH^{+}\text{+ OH}\text{ }^{-}\overset{\quad\quad}{\rightarrow}H_{2}O

D

H+ + e−→ H2 .H^{+}\text{ + }\text{e}^{-}\overset{\quad\quad}{\rightarrow}\text{ }\text{H}_{2}\text{ .}

Answer

2 H2O + O2 + 4 e−→ 4 OH−\text{2 }\text{H}_{2}\text{O + }\text{O}_{2}\text{ + 4 }\text{e}^{-}\overset{\quad\quad}{\rightarrow}\text{ 4 O}\text{H}^{-}

Explanation

Solution

H2–O2 fuel cell

At anode : 2OH– + H2 ⟶\longrightarrow 2H2O + 2e–

At cathode : 2 H2O + O2 + 4e– ⟶\longrightarrow 4OH–