Question
Question: In Gr (V), \[{\left( {N{H_4}} \right)_2}C{O_3}\] is added to precipitate out carbonates. What happen...
In Gr (V), (NH4)2CO3 is added to precipitate out carbonates. What happens when Na2CO3 is added instead of (NH4)2CO3 ?
(A) CaCO3 will be soluble in Na2CO3
(B) MgCO3 will be precipitated out
(C) Na2CO3 will increase the solubility of fifth group carbonates
(D) Both (A) and (B)
Solution
The salt analysis for the basic radicals (cationic part of salt) and acid radicals (anionic part of salt) is done separately. The basic radicals are divided into various groups on the basis of their chemical properties and solubility. Each group has a different group reagent which helps the basic radicals to separate out in the form of their insoluble salt.
Complete answer:
We know that the salt analysis for the basic radicals (cationic part of salt) and acid radicals (anionic part of salt) is done separately. The basic radicals are divided into various groups on the basis of their chemical properties and solubility in group reagents. Every group have different set of reagents known as group reagents which help the basic radicals to separate out in the form of their insoluble salt.
The group V basic radicals are Ca2+,Ba2+ and Sr2+ .
Now, the group V reagent is (NH4)2CO3 in presence of NH4Cl . If we use Na2CO3 instead of (NH4)2CO3 then, due to the high ionization of Na2CO3 the concentration of CO32− ions increase and hence, it will exceed the solubility of group V basic radicals as well as that of Mg2+ . So, Magnesium (which is group VI cation) will also get precipitated in the form of its carbonate.
Hence, the correct option is (B) MgCO3 will be precipitated out.
Note:
Each group has different group reagents in salt analysis such as group I is dilute HCl and group II is Hydrogen sulphide in presence of dil. HCl. For group III, it is NH4OH in presence of NH4Cl and for group IV it is Hydrogen sulphide in ammoniacal medium. For group V, the group reagent is (NH4)2CO3 in presence of NH4Cl and for group VI it is NH4OH and Na2HPO4 .