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Question: In going from one city to another, a car travels \(75km\) north, \(60km\) north-west and \(20km\) ea...

In going from one city to another, a car travels 75km75km north, 60km60km north-west and 20km20km east. The magnitude of displacement between the two cities is (take2=0.7\sqrt{2}=0.7)
A. 170km\text{A}\text{. }170km
B. 137km\text{B}\text{. 137km}
C. 119km\text{C}\text{. }119km
D. 140km\text{D}\text{. }140km

Explanation

Solution

Hint: For finding the displacement of a car, we have to take the distance travelled in directions in the vector form. Take x-axis as the West-East line and y-axis as the North-South line. After finding the displacement of each turn of the car, we will find the magnitude of displacement between two cities.

Formula used:
s=sfsis={{s}_{f}}-{{s}_{i}}

Complete step by step answer:
Displacement is a vector quantity which refers to “how far from a point an object is”, it is an object’s overall change in position. We can say, a displacement is a vector whose length is the shortest distance between the two points. Displacement is calculated by finding the final distance of the object from a fixed point and then subtracting its initial distance from the same point.
Displacement is represented by the symbol ss
s=sfsis={{s}_{f}}-{{s}_{i}}
s= displacement si= initial position sf= final position \begin{aligned} & s=\text{ displacement} \\\ & {{s}_{i}}=\text{ initial position} \\\ & {{s}_{f}}=\text{ final position} \\\ \end{aligned}

Displacement of car in North direction = 75j^75\widehat{j}
Displacement of car in North-West direction = 60cos45i^+60sin45j^-60\cos {{45}^{\circ }}\widehat{i}+60\sin {{45}^{\circ }}\widehat{j}
Displacement of car in East direction = 20i^20\widehat{i}
Final position of the car = (602+20)i^+(602+75)j^\left( \dfrac{-60}{\sqrt{2}}+20 \right)\widehat{i}+\left( \dfrac{60}{\sqrt{2}}+75 \right)\widehat{j}
=22i^+117j^=-22\widehat{i}+117\widehat{j}
Finding magnitude of the displacement of the car,
=(117)2+(22)2=14173=119=\sqrt{{{(117)}^{2}}+{{(22)}^{2}}}=\sqrt{14173}=119
Displacement of the car is 119km119km
Hence, the correct option is C.

Additional information:
Distance is the measure of how much ground a body has covered. It is a scalar quantity. Displacement refers to how far a body lies from a fixed point; it is the body's overall change in the position.
Speed is defined as the rate at which a body covers the distance. It is a scalar quantity. Velocity refers to the rate at which a body changes its position. It is a vector quantity.

Note: Students should be careful while calculating the displacement of the object in different directions. Keep in mind that positive x-axis is the East direction while negative x-axis is the West direction. Similarly, when the body is moving towards the North, it is taken along positive y-axis while going towards South is taken along negative y-axis.