Question

In given reaction, A and B are is treated with $C{H_3}CN$ and then hydrolysed.

In another reaction is treated with ethyl acetate and then hydrolysed.

A.

B.

C.

D.

Answer 1

We have to know that cyclohexylmagnesium bromide undergoes substitution reaction with $C{H_3}CN$ and $C{H_3}COO{C_2}{H_5}$. An intermediate compound is formed when they are substituted in cyclohexylmagnesium bromide and upon hydrolysis a cyclic ketone is formed.

Complete step by step answer:

When we react cyclohexylmagnesium bromide with $C{H_3}CN$ and $C{H_3}COO{C_2}{H_5}$ the product formed in both the cases will be cyclohexyl methyl ketones.
Let us first write the reaction of cyclohexylmagnesium bromide with $C{H_3}CN$.
Methyl cyanide on reaction with cyclohexylmagnesium bromide gives an intermediate; the intermediate on hydrolysis gives cyclohexyl methyl ketones.

We can see the product formed is 1-cyclohexylethanol when methyl cyanide is reacted with cyclohexylmagnesium bromide.
Let us now go to the second reaction, cyclohexyl magnesium bromide when treated with ethyl acetate, we will again get the product cyclohexyl methyl ketones.
Ethyl acetate on reaction with cyclohexylmagnesium bromide gives an intermediate; the intermediate on hydrolysis gives cyclohexyl methyl ketones.

We can see the product formed is 1-cyclohexylethanol when methyl cyanide is reacted with cyclohexylmagnesium bromide.
In both the reactions, the product formed is 1-cyclohexylethanone.

Therefore, Option (B) is correct.

Note: Cyclohexyl Ethanone (or) cyclohexyl methyl ketones have a molecular formula of ${C_8}{H_{10}}O$. They are otherwise known as acetylcyclohexane and its molar mass is $126.2g/mol$. It has a boiling point of ${180.5^ \circ }C$. We generally use acetonitrile (or) methyl cyanide as polar aprotic solvent in organic synthesis. It is also used to purify butadiene. We can use acetonitrile as a solvent in the production of photographic film and pharma industry. Ethyl acetate is a condensation product of ethanoic acid and ethyl alcohol.