Question

In given figure, a wire loop has been bent so that it has three segments ab (a quarter circle), bc (a square corner) &ca (straight line). Here are three choices for a magnetic field through the loop.

• A. i₁ > i₂ > i₃
• B. i₂ > i₁ > i₃
• C. i₃ > i₂ > i₁
• D. i₁ = i₂ = i₃

Answer 1

Answer: (B)

i₂ > i₁ > i₃

Answer 2

i₁ = = = $\frac { \mathrm { d } } { \mathrm { dt } }$ $\left[ 5 \mathrm { t } \times \frac { \pi \mathrm { a } ^ { 2 } } { 4 } \right]$ × $\frac { 1 } { \mathrm { R } }$

= $\frac { 5 \pi \mathrm { a } ^ { 2 } } { 4 \mathrm { R } }$

i₂ = × = × $\frac { 1 } { \mathrm { R } }$ =

i₃ = $\frac { \mathrm { d } \phi _ { 3 } } { \mathrm { dt } }$ × $\frac { 1 } { \mathrm { R } }$ = $\frac { \mathrm { d } \left[ 0.5 \mathrm { a } ^ { 2 } \right] } { \mathrm { dt } }$ × =

∴ i₂ > i₁ > i₃