Question

In given circuit, the value of currents I1, I2 and I3 are

• A. $\sigma_{1}$
• B. $\sigma_{2}$
• C. $\sigma_{1} + \sigma_{2}$
• D. $\frac{\sigma_{1} + \sigma_{2}}{2}$

Answer 1

Answer: (A)

$\sigma_{1}$

Answer 2

:

Applying kirchhoff’s voltage law,

In loop I, $- 27 - 6I_{2} - 2I_{1} + 24 = 0$

$6I_{2} + 2I_{1} = - 3$ …(i)

In loop II, $- 27 - 6I_{2} + 4I_{3} = 0 6I_{2} - 4I_{3} = - 27$ …(ii)

At junction P, $I_{1} - I_{2} - I_{3} = 0$ …(iii)

Solving equations (i), (ii) and (iii) we get

$I_{1} = 3A,I_{2} = - 3/2A,I_{3} = 9/2A.$