Biology Question on Principles of Inheritance and Variation

Question

In garden pea, round shape of seeds is dominant over wrinkled shape. A pea plant heterozygous for round shape of seed is selfed and 1600 seeds produced during the cross are subsequently germinated. How many seedlings would have the parental phenotype ?

Answer 1

Solution

Since this pea plant is heterozygous for round shape, its genotype would be Rr.
Parents: Rr $\times$ Rr
$\quad \,\,\,\,\,\,\,\,\,{v}$ (selfing)
Progeny: RR Rr Rr rr
Phenotypically, the ratio will be 3 : 1 i.e., only rr seedlings will show wrinkled phenotype, rest will show round shape.
1200 $\to$ Round shape (RR, Rr)
400 $\to$ Wrinkled (rr)