Question

In Freundlich adsorption isotherm, slope of AB line is :

• A. $\log n$ with $( n >1)$
• B. $n$ with $( n , 0.1$ to 0.5$)$
• C. $\log \frac{1}{n}$ with $(n<1)$
• D. $\frac{1}{ n }$ with $\left(\frac{1}{ n }=0\right.$ to $\left.1\right)$

Answer 1

Answer: (D)

$\frac{1}{ n }$ with $\left(\frac{1}{ n }=0\right.$ to $\left.1\right)$

Answer 2

$\frac{x}{m}=K(P)^{1 / n}$
$\log \left(\frac{ x }{ m }\right)=\log K +\frac{1}{ n } \log P$
$y = c + mx$
$m =1 / n$ so slope will be equal to $1 / n$