Question
Question: In figure are shown charges q<sub>1</sub> = + 2 × 10<sup>–8</sup>C and q<sub>2</sub> = – 0.4 × 10<su...
In figure are shown charges q1 = + 2 × 10–8C and q2 = – 0.4 × 10–8C. A charge q3 = 0.2 × 10–8C in moved along the arc of a circle from C to D. The potential energy of q3

A
Will increase approximately by 76%
B
Will decreases approximately by 76%
C
Will remain same
D
Will increases approximately by 12%
Answer
Will decreases approximately by 76%
Explanation
Solution
Initial potential energy of q3 Ui=(0.8q1q3+1q2q3)×9×109
Final potential energy of q3 Uf=(0.8q1q3+0.2q2q3)×9×109
Change in potential energy = Uf – Ui
Now percentage change in potential energy =uiUf−Ui×100
=q3(0.8q1+1q2)q2q3(0.21−1)×100 On putting the values –−76%
