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Question

Chemistry Question on Adsorption

In figure, a straight line is given for Freundrich Adsorption (y=3x+2505)(y=3 x+2505) The value of 1n\frac{1}{ n } and logK\log K are respectively
straight line

A

3 and 2.5052.505

B

3 and 0.70330.7033

C

0.30.3 and log2.505\log 2.505

D

0.30.3 and 0.70330.7033

Answer

3 and 2.5052.505

Explanation

Solution

The correct answer is (A) : 3 and 2.505
mx​=Kp1/n
logmx​=logk+n1​logP
Y=3x+2.505,n1​=3,logK=2.505)