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Question

Chemistry Question on The solid state

In fcc arrangement of A and B atoms, where A atoms are at the corners of the unit cell, B atoms at the face centres. Two atoms are missing from two corners in each unit cell, then the simplest formula of the compound is

A

A7B6A_7B_6

B

A6B7A_6B_7

C

A7B24A_7B_{24}

D

AB4AB_4

Answer

AB4AB_4

Explanation

Solution

A-atoms are present at 6 corners out of 8. Thus, number of A-atoms per unit cell =18×6=68=34= \frac{1}{8} \times 6 = \frac{6}{8} = \frac{3}{4} Number of B-atoms per unit cell =12×6=3= \frac{1}{2} \times 6 = 3 A:B=34:3=1:4A : B =\frac{3}{4} : 3 =1 : 4 Thus, formula is AB4.AB_{4}.