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Question: In expansion of (1 + x + x<sup>2</sup> ................. + x<sup>27</sup>) (1 + x + x<sup>2</sup> .....

In expansion of (1 + x + x2 ................. + x27) (1 + x + x2 ... + x14)2, coefficient of x28 is –

A

190

B

220

C

224

D

204

Answer

224

Explanation

Solution

coefficent of xr in (1 – x)–n is n+r–1Cr

\ given product = (1x28)(1x)\frac { \left( 1 - x ^ { 28 } \right) } { ( 1 - x ) } (1x151x)2\left( \frac{1 - x^{15}}{1 - x} \right)^{2}

= (1 – x28) (1 – 2x15) (1 – x)–3

\ Coefficient of x28 in (1 – 2x15 – x28)(1 – x)–3 is

= 30C2 – 2.15C2 –1= 224