Question
Question: In expansion of (1 + x + x<sup>2</sup> ................. + x<sup>27</sup>) (1 + x + x<sup>2</sup> .....
In expansion of (1 + x + x2 ................. + x27) (1 + x + x2 ... + x14)2, coefficient of x28 is –
A
190
B
220
C
224
D
204
Answer
224
Explanation
Solution
coefficent of xr in (1 – x)–n is n+r–1Cr
\ given product = (1−x)(1−x28) (1−x1−x15)2
= (1 – x28) (1 – 2x15) (1 – x)–3
\ Coefficient of x28 in (1 – 2x15 – x28)(1 – x)–3 is
= 30C2 – 2.15C2 –1= 224