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Question: In equimolar solution of glucose, \(NaCl\) and \(BaCl_{2}\), the order of osmotic pressure is as fol...

In equimolar solution of glucose, NaClNaCl and BaCl2BaCl_{2}, the order of osmotic pressure is as follow.

A

Glucose >NaCl>BaCl2> NaCl > BaCl_{2}

B

NaCl>BaCl2>NaCl > BaCl_{2} > Glucose

C

BaCl2>NaCl>BaCl_{2} > NaCl > Glucose

D

Glucose >BaCl2>NaCl> BaCl_{2} > NaCl

Answer

BaCl2>NaCl>BaCl_{2} > NaCl > Glucose

Explanation

Solution

BaCl2BaCl_{2} ⇒ Ba2++2Cl−=3Ba^{2 +} + 2Cl^{-} = 3ion

NaClNaCl ⇒ Na++Cl−=2Na^{+} + Cl^{-} = 2ion

Glucose ⇒ No ionization ∴BaCl2>NaCl>GlucoseBaCl_{2} > NaCl > \text{Glucose}