In dry cell the reaction which takes place at the zinc anode... | CHEMISTRY - BATTERIES | SolveeIt | Solveeit

Today, August 19

Question

In dry cell the reaction which takes place at the zinc anode is.

A

$M_{(aq)}^{n +} + ne^{-} \rightarrow M_{(s)}$

B

$E_{cell} = Eº - \frac{0.0591}{n}\log\frac{1}{\lbrack M^{n +}\rbrack}$

C

$\Delta_{m}$

D

$\rho l/A$

Answer

$E_{cell} = Eº - \frac{0.0591}{n}\log\frac{1}{\lbrack M^{n +}\rbrack}$

Explanation

Solution

At anode: $Zn_{(s)} \rightarrow Zn^{2 +} + 2e^{-}$ .