Question

In $Cu$-ammonia complex, the state of hybridization of $Cu^{+2}$ is

• A. $sp^{3}$
• B. $d^{3}s$
• C. $sp^{2}f$
• D. $dsp^{2}$

Answer 1

Answer: (D)

$dsp^{2}$

Answer 2

$Cu$-ammonia complex is $\left[ Cu \left( NH _{3}\right)_{4}\right]^{2+}$

$NH_3$, being strong field ligand, shifts the unpaired electron to higher level.