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Question

Question: In complex numbers \[z\mathop z\limits^\\_ = 0\] if and only if (A) \(\operatorname{Re} \left( z ...

In complex numbers z\mathop z\limits^\\_ = 0 if and only if
(A) Re(z)=0\operatorname{Re} \left( z \right) = 0
(B) z=0z = 0
(C) Im(z)=0\operatorname{Im} (z) = 0
(D) Re(z)=Im(z)\operatorname{Re} (z) = \operatorname{Im} (z)

Explanation

Solution

To solve this problem we have to assume z=a+ibz = a + ib and after that we put this in z\mathop z\limits^\\_ = 0 and solve them.In z=a+ibz = a + ib, Real part of zz is aa and imaginary part of zz is bb And z=a2+b2\left| z \right| = \sqrt {{a^2} + {b^2}} .Using these definitions and formulas we try to get the answer.

Complete step-by-step answer:
We assume that z=a+ibz = a + ib
And modulus of zz
z=a2+b2\left| z \right| = \sqrt {{a^2} + {b^2}}
So now given z\mathop z\limits^\\_ = 0
As we know that z\mathop z\limits^\\_ = {\left| z \right|^2}
Now so from above given equation we can write
z\mathop z\limits^\\_ = {\left| z \right|^2} = 0
z=a2+b2\because \left| z \right| = \sqrt {{a^2} + {b^2}}
So z2=a2+b2{\left| z \right|^2} = {a^2} + {b^2}
And we know that
z2=0{\left| z \right|^2} = 0
So z2=a2+b2=0{\left| z \right|^2} = {a^2} + {b^2} = 0
This condition is possible only when a=0a = 0 and b=0b = 0
So from this we can say z=0+i0z = 0 + i0
So from this we say that
Re(z)=0\operatorname{Re} \left( z \right) = 0 as well as Im(z)=0\operatorname{Im} (z) = 0
And z=0z = 0 because the real part and imaginary part are both zero.
Now as we see Re(z)=0\operatorname{Re} \left( z \right) = 0 as well as Im(z)=0\operatorname{Im} (z) = 0
From this we can say Re(z)=Im(z)=0\operatorname{Re} (z) = \operatorname{Im} (z) = 0
So all four options are the correct answer.

So, the correct answer is “All options”.

Note: A complex number z=x+iyz = x + iy is a purely real if its imaginary part is 0, i.e. Im(z)\operatorname{Im} (z) = 0 and purely imaginary if its real part is 0 i.e. Re(z)\operatorname{Re} (z) = 0.Two complex numbers z1=x1+iy1{z_1} = {x_1} + i{y_1} and z2=x2+iy2{z_2} = {x_2} + i{y_2} are equal, if x1=x2{x_1} = {x_2} and y1=y2{y_1} = {y_2} i.e. Re(z1)\operatorname{Re} \left( {{z_1}} \right) = Re(z2)\operatorname{Re} ({z_2}) and Im(z1)\operatorname{Im} ({z_1}) = Im(z2)\operatorname{Im} ({z_2}).
Order relation “greater than’’ and “less than” are not defined for complex numbers.
Important identities:
1. Additive identity z + 0 = z = 0 + z
Here, 0 is an additive identity.
2. Multiplicative identity: z×1z \times 1 = zz = 1×z1 \times z
3. Conjugate of Complex Number: Let z=x+iyz = x + iy, if ‘i’ is replaced by (i - i), then said to be conjugate of the complex number z and it is denoted by \mathop z\limits^\\_ , i.e. \mathop z\limits^\\_ = x - iy.