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Question: In CH<sub>4</sub> molecule, there are four C – H bounds. If two adjacent bonds are in \(\widehat{i} ...

In CH4 molecule, there are four C – H bounds. If two adjacent bonds are in i^+j^+k^\widehat{i} + \widehat{j} + \widehat{k}and i^j^k^\widehat{i} - \widehat{j} - \widehat{k} direction, then fin d the angle between these bonds.

A

sin-1(13)\left( \frac{- 1}{3} \right)

B

cos-1(13)\left( \frac{1}{3} \right)

C

sin-1(13)\left( \frac{1}{3} \right)

D

cos-1(13)\left( \frac{- 1}{3} \right)

Answer

cos-1(13)\left( \frac{- 1}{3} \right)

Explanation

Solution

cosθ=(i^+j^+k^)(i^j^k^)3.3=13\cos\theta = \frac{\left( \widehat{i} + \widehat{j} + \widehat{k} \right)\left( \widehat{i} - \widehat{j} - \widehat{k} \right)}{\sqrt{3}.\sqrt{3}} = \frac{- 1}{3}

θ = cos-1(13)\left( \frac{- 1}{3} \right)