Question

In $CH_{3}CH_{2}Br,\%$ of Br is.

• A. 80
• B. 75
• C. 70
• D. 7

Answer 1

Answer: (B)

75

Answer 2

% of Br $= \frac{\text{Massof}Br}{\text{Mass of organic compound}} \times 100 = \frac{80}{109} \times 100 = 73.39\%$or approx. 75%.