Question

In Carius method of estimation of halogen, 0.45 g of an organic compound gave 0.36 g of AgBr. Find out the percentage of bromine in the compound.
(Molar masses: AgBr = 188 g mol-1; Br = 80 g mol-1)

• A. 34.04%
• B. 40.04%
• C. 36.03%
• D. 38.04%

Answer 1

Answer: (A)

34.04%

Answer 2

The correct answer is (A):
188g of AgBr = 80g of Br
0.36g of AgBr = $\frac{80}{188}$×0.36
Percentage of Br in given organic compound
= 80×$\frac{0.36}{188}$×0.45×100
= 34.04%