Question

In Carius method of estimation of halogen, $0.15\, g$ of an organic compound gave $0.12\, g$ of $AgBr$. What is the percentage of bromine in the compound?

• A. $68.08 \%$
• B. $34.04\%$
• C. $42.1 \%$
• D. $50\%$

Answer 1

Answer: (B)

$34.04\%$

Answer 2

Molar mass of $AgBr = 108 + 80 = 188 \,g\, mol^{-1}$ Percentage of $Br_{2}=\frac{80}{188}\times\frac{0.12}{0.15}\times100$ $=34.04\%$