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Chemistry Question on Atomic Models

In astronomical observations, signals observed from the distant stars are generally weak. If the photon detector receives a total of 3.15 × 10–18 J from the radiations of 600 nm, calculate the number of photons received by the detector.

Answer

From the expression of energy of one photon (E), E = hcλ\frac{hc}{\lambda}
Where, λ\lambda = wavelength of radiation
h = Planck's constant
c = velocity of radiation
Substituting the values in the given expression of E:
E = (6.626×10−34Js)(3×108ms−1)600×10−9m\frac{(6.626\times 10^{-34}Js)(3\times10^8ms^{-1})}{600\times10^{-9}m}
E = 3.313× 1019 J
Energy of one photon = 3.313 × 1019 J
Number of photons received with 3.15 × 1018 J energy
= 3.15×10−18J3.131×10−19J=9.5J\frac{3.15\times 10^{-18}J}{3.131\times10^{-19}J}=9.5J