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Question

Chemistry Question on Structure of atom

In astronomical observations, signals observed from the distant stars are generally weak. If the photon detector receives a total of 3.15 ? 10−18J10^{-18} J from the radiation of 600 nm, calculate the number of photons received by the detector.

A

4

B

9

C

6

D

7

Answer

9

Explanation

Solution

Total energy =3.15×10−18J3.15\times10^{-18} J Wavelength, λ=600nm=600×10−9m\lambda=600 nm =600\times10^{-9}m No. of photons received by detector = ? Energy per photon=hcλ\frac{h c}{\lambda} =6.626×10−34Js×(3×108ms−1)600×10−9m=3.313×10−19J=\frac{6.626\times10^{-34}J s\times\left(3\times10^{8}m s^{-1} \right)}{600\times10^{-9} m}=3.313\times10^{-19} J So, no. of photons received by the detector =3.15×10−18J3.313×10−19J=9.5=9=\frac{3.15\times10^{-18} J}{3.313\times10^{-19} J}=9.5=9