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Question: In arrangement shown. has two non-condu. Balne sheet with charge density, and a non conducting spher...

In arrangement shown. has two non-condu. Balne sheet with charge density, and a non conducting sphere with volume charge density? choose the correct relation between the magnitude of electric field at A.B.C. and D.

A

EA_{A} ≠ EB_{B} ED_{D} > EC_{C}

B

EA_{A} = EB_{B} ED_{D} > Ec_{c}

C

EA_{A} ≠ EB_{B} EC_{C} > ED_{D}

D

EA_{A} = EB_{B} ED_{D} > EC_{C}

Answer

Eₐ = Eᵦ and E_D > E_C.

Explanation

Solution

  1. The two charged non‐conducting sheets produce uniform electric fields. Their contributions are independent of a small displacement so that at points A and B (both lying on the same side of the right sheet) the sheet–field contributions are equal.

  2. Moreover, the superposition of the sheet–fields is such that, outside the region between the sheets the contributions add up. In particular, on the right (point D) the fields from both sheets reinforce one another, whereas on the left (point C) the fields partly cancel.

  3. Thus, the magnitude of the field satisfies:
    Eₐ = Eᵦ and E_D > E_C.

Explanation (minimal):

  • Uniform fields from the sheets mean points A and B have equal contributions → Eₐ = Eᵦ.
  • Outside the sheets the forces add (right side, at D) while on the left (at C) they partially cancel → E_D > E_C.