Question

In aqueous alkaline solution, two electron reduction of $HO^-_2$ gives

• A. $HO^-$
• B. $H_2O$
• C. $O_2$
• D. $O^-_2$

Answer 1

Answer: (A)

$HO^-$

Answer 2

In aqueous alkaline solution, two electron reduction of $HO _{2}^{-}$gives $\overset{-}{ O } H$. The reaction is as follows:
$H _{2} O _{2} \rightleftharpoons H ^{+}+ HO _{2}^{-}$
$HO _{2}^{-}+ H _{2} O +2 e ^{-} \longrightarrow 3 \overset{-}{ O } H$