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Question

Mathematics Question on Triangles

In any ABC△ABC, the value of sin(A+B2)\sin \left( \frac{A + B}{2} \right) is

A

sin(C2)\sin \left( \frac{C}{2} \right)

B

cos(C2)\cos \left( \frac{C}{2} \right)

C

sin(AB2)\sin \left( \frac{A-B}{2} \right)

D

cos(AB2)\cos \left( \frac{A-B}{2} \right)

Answer

cos(C2)\cos \left( \frac{C}{2} \right)

Explanation

Solution

The correct option is (B): cos(C2)\cos \left( \frac{C}{2} \right)