Question
Question: In another case , p and 2p are the first and second terms of an arithmetic progression. The nth term...
In another case , p and 2p are the first and second terms of an arithmetic progression. The nth term is 336 and the sum of the first n terms is 7224. Write down two equations in n and p and hence find the value of n and p.
Solution
With the given terms we can find the common difference and using the nth term formula an=a+(n−1)d we can find a equation substituting in the formula of Sn=2n[2a+(n−1)d]. we can find the value of n and p.
Complete step by step solution:
We are given that the first two terms of an AP are p and 2p
⇒a=p,a2=2p
The common difference is given by subtracting the first term from the second term
⇒ 2p – p = p
The nth of the sequence is given by
⇒an=a+(n−1)d
Here we have the nth term to be 336
⇒336=p+(n−1)p ⇒336=p+pn−p=pn ⇒np=336
We know that the sum of the first n terms is given by
⇒Sn=2n[2a+(n−1)d]
⇒7224=2n[2p+(n−1)p] ⇒7224=2n[2p+np−p] ⇒7224=2n[p+np]
Substituting the value of np we get
⇒7224=2n[p+336] ⇒7224=2np+2336n ⇒7224=2336+168n ⇒7224=168+168n ⇒7224=168(1+n) ⇒1687224=n+1 ⇒43=n+1 ⇒n=42
Substituting this in np = 336
⇒42p=336 ⇒p=42336=8
Therefore the value of p = 8 and n = 42
Note:
- In an Arithmetic Sequence the difference between one term and the next is a constant.
- We can find the common difference of an AP by finding the difference between any two adjacent terms.
- If we know the initial term, the following terms are related to it by repeated addition of the common difference.