Question

In $\angle FAsF$ bond angle $As{F_3}C{l_2}$ molecule is:
A. ${90^\circ }$ and ${180^\circ }$
B. ${120^\circ }$
C. ${90^\circ }$
D.${180^\circ }$

Answer 1

As it has 5 electrons in the external most shell, it structures a three-sided bipyramidal structure in the above compound goes on the edges of the triangle and $Cl$ on the 2 hub positions (to achieve balance).So $FAsF$ bond is unpredictable.

Complete step by step answer:
The appropriate answer is ${90^\circ }$ and ${180^\circ }$ in light of the fact that hub positions favour high electronegative iotas so 2 fluorines on hub and one on equatorial.
Pivotal positions lean toward high electronegative molecules because of bent's rule as their repugnance is more for electronegative particles.
So, the correct answer is Option A.

Note: Bond angles also contribute to the shape of a molecule. Bond angles are the angles between adjacent lines representing bonds. The bond angle can help differentiate between linear, trigonal planar, tetrahedral, trigonal-bipyramidal, and octahedral. Basically, bond angle is revealing to us that electrons don't prefer to be close to one another. Electrons are negative. Two negatives don't draw in. How about we make a similarity. For the most part, an adverse individual is viewed as awful or mean and you would prefer not to converse with a contrary individual. One pessimistic individual is awful enough, yet in the event that you have two put together...that's simply awful. Along these lines, they will be far away from one another.
$As{F_3}C{l_2}$ before it deteriorates above C in fluid stage (1, p. 100) has the accompanying three-sided bipyramidal structure with two hub F iotas. Precious stone structure of strong compound however identifies with the blended halide of$AsC{l_4}[As{F_6}]$ with discrete $AsC{l_4}$ and $As{F_6}$ units.