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Question: In an oscillating spring mass system, a spring 9 is connected to a box filled with sand. As the box ...

In an oscillating spring mass system, a spring 9 is connected to a box filled with sand. As the box oscillates, sand leaks slowly out of the box vertically so that the average frequency ω(t)\omega(t) and average amplitude A(t)A(t) of the system change with time tt. Which one of the following options schematically depicts these changes correctly?

A

Option 1

B

Option 2

C

Option 3

D

Option 4

Answer

3

Explanation

Solution

The angular frequency of a spring-mass system is ω=k/m\omega = \sqrt{k/m}. As sand leaks, the mass m(t)m(t) decreases, causing the frequency ω(t)\omega(t) to increase with time.

For slowly varying mass, the adiabatic invariant E/ωE/\omega is approximately constant. The energy of the oscillator is E=12kA2E = \frac{1}{2}kA^2. Thus, 12kA2k/m=constant\frac{\frac{1}{2}kA^2}{\sqrt{k/m}} = constant, which implies A2m=constantA^2 \sqrt{m} = constant, or Am1/4A \propto m^{-1/4}. Since the mass m(t)m(t) is decreasing with time, the amplitude A(t)A(t) increases with time.

Therefore, both the average frequency and the average amplitude of the system increase with time.