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Question

Physics Question on Alternating current

In an oscillating LC circuit the maximum charge on the capacitor is The charge on the capacitor when the energy is stored equally between the electric and magnetic field is

A

Q/2Q/2

B

Q/2Q/ \sqrt {2}

C

Q/3Q/ \sqrt {3}

D

QQ

Answer

Q/2Q/ \sqrt {2}

Explanation

Solution

Total energy stored =12Q2C=\frac{1}{2} \frac{Q^{2}}{C} At any time electrostatic energy is equal to magnetic energy. 12Q2C=1q22+12LI2\frac{1}{2} \frac{ Q ^{2}}{ C }=\frac{1 q ^{2}}{2}+\frac{1}{2} LI ^{2} ..(1) Since q22C=LI22\frac{ q ^{2}}{2 C }=\frac{ LI ^{2}}{2} Equation (1) becomes, 1Q22q2C=qC\frac{1 Q^{2}}{2} \frac{q^{2}}{C}=\frac{q}{C} q=Q2q=\frac{Q}{\sqrt{2}} Where qq is the charge on capacitor at this instant.